find the value of k for which the pair of linear equation X + 2y - 5 = 0 and 3x + 65 + K equal to zero represent coincident lines
Answers
Step-by-step explanation: if lines are coincident then use formula
a1/a2 = b1/b2 = c1/c2 so here 1/3 = 2/65 =-5/k
1/3 =-5/k ⇒ k = -15 and k = -325/2
k = -15 for which the pair of linear equation x + 2y - 5 = 0 and 3x + 6y + K = 0 represent coincident lines
Step-by-step explanation:
x + 2y - 5 = 0
=> x + 2y = 5
3x + 6y + k = 0
=> 3x + 6y = - k
pair of linear equation represent coincident lines if
1/3 = 2/6 = 5/(-k)
=> 1/3 = 1/3 = -5/k
=> k = -15
3x + 6y - 15 = 0
Dividing by 3 both sides
=> x + 2y - 5 = 0 same as x + 2y - 5 = 0
k = -15
k = -15 for which the pair of linear equation x + 2y - 5 = 0 and 3x + 6y + K = 0 represent coincident lines
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