Question

find the perimeter of a semi circle if its area is 1232cmsquare​

Answer 1

Answer:

Perimeter of Semicircle = 143.92cm

Step-by-step explanation:

We Have :-

Area of Semicircle = 1232cm²

To Find :-

Perimeter

Formula Used :-

Area of Semicircle = 1/2 ( π r² )

Perimeter of Semicircle = r ( 2 + π )

Solution :-

$Area\ of\ Semicircle = \frac{1}{2} \pi r^{2} \\\\1232 = \frac{1}{2}\pi r^{2} \\\\2464 = \pi r^{2} \\\\r^{2}= \frac{2464*7}{22} \\\\r^{2}= 784\\\\r = 28 cm\\\\Perimeter = r ( 2+\pi )\\\\= 28(2 +3.14)\\\\= 28*5.14\\= 143.92 cm$

Perimeter of Semicircle = 143.92cm

Answer 2

Answer:

232 cm

                                       

Step-by-step explanation:

AREA OF SEMI CIRLCE = $\frac{\pi r^{2} }{2}$

1232 = $\frac{22r^{2} }{14}$

$r^{2} = \frac{1232(14)}{22}$

$r = \sqrt{ \frac{1232(14)}{22}}$

$r = \sqrt{784}$

r = 28cm

perimeter of a semi circle = $2\pi r$ + 2r

                                        = $2$ × $\frac{22}{7}$ × 28 + 2(28)

                                        =2 × 22 × 4 + 56

                                       = 176+56

                                       =232 cm