Question

if a, b and c are three factors of p^3-7P+6,then the value of a+b+c will be​

Answer 1

Hey there,

Here's your answer:

$p^3 - 7p + 6\\\\p^3 - 7p + 6 = 0\\\\p(p^2 -7) + 6 = 0\\\\p(p^2-7+6) = 0\\\\p(p^2 -1) = 0\\\\p(p+1)(p-1)=0\\\\p=0, -1, 1.\\\\Therefore, a = 0, b = -1, c = 1.\\\\a+b+c = 0-1+1\\=0$

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Hope it helps.

Have a great day! ;)