Find the value of k for which the pairof equation 2x+ky+3=o and 4x +6y-5=0 represent parallel lines.
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For 2equations to be represented as parallel lines
A1/A2 = b1/b2 ≠ c1/C2---(1)
here, A1 is 2
b1 is k and c1 is 3---(2)
similarly, a2 is 4, b2 is 6 and C2= -5---(3)
Using (2) and (3) in (1).
we get,
2/4=k/6≠3/-5
Therefore, 2/4=k/6
1/2 = k/6.
Solving, we get k=3.
Hope this helps. Please mark as brainliest. :-)
A1/A2 = b1/b2 ≠ c1/C2---(1)
here, A1 is 2
b1 is k and c1 is 3---(2)
similarly, a2 is 4, b2 is 6 and C2= -5---(3)
Using (2) and (3) in (1).
we get,
2/4=k/6≠3/-5
Therefore, 2/4=k/6
1/2 = k/6.
Solving, we get k=3.
Hope this helps. Please mark as brainliest. :-)
Answered by
1
Answer:
Step-by-step explanation:
As the lines are parallel slope of both lines are same
∴2x+ky+3=0
ky=-2x-3
y=(-2/k)x-3/k
∴m₁=-2/k
4x+6y-5=0
6y=-4x+5
y=(-4/6)x+5/4
∴m₂=-2/3
But m₁=m₂
-2/k=-2/3
∴k=3
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