Question

Find the value of k for
Which the point (2,-2)
lies on
the graph of linear epuations 3x+ 2y+k =0​

Answer 1

3(2)+2(-2)+k=9

6-4+k=0

k=-2.....

..... Hope this will help you...

Answer 2

Answer:

let k be 1 now

then we will put value as

3×2=6

2×-2= -4

6+(-4)+k=0

6-4+k=0

2+k=0

k=2 is your answer