find the value of k for which the point a (k 5 ) B(0 1) AND C (2 -3) ARE COLINEAR POINT
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since the points are colinear,
slope of AB=slope of BC
1-5/0-k = -3-1/2-0
-4/-k=-4/2
4/k=-2
k= -2
slope of AB=slope of BC
1-5/0-k = -3-1/2-0
-4/-k=-4/2
4/k=-2
k= -2
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