Question

There are three bottles of mixture of syrup and water of ratios 2:3, 3:4 and 7:5. 10 Litres of first and 21 Litres of second bottles are taken. How much quantity from third bottle is to be taken so that final mixture from three bottles will be of ratios 1:1.

Answer 1

first bottle has 10 litres and ratio of syrup and water is 2 : 3
so, amount of syrup = 10 × 2/5 = 4 litres
amount of water = 10 × 3/5 = 6 litres

similarly , 2nd bottle has 21 litres and ratio of syrup and water is 3 : 4 .
so, amount of syrup = 21 × 3/7 = 9 litres
amount of water = 21 × 4/7 = 12 litres

Let in 3rd bottle has x litres and ratio of syrup and water is 7 : 5
so, amount of syrup = 7x/12 litres
amount of water = 5x/12 litres

finally, mixture ratio is 1 : 1
means ,total amount of syrup =total amount of water
=> 4 + 9 + 7x/12 = 6 + 12 + 5x/12
=> 7x/12 - 5x/12 = 18 - 13 = 5
=> x/6 = 5
=> x = 30

hence, 30 litres of quantity is to be taken in 3rd bottle.

Answer 2

Answer:

30 right answer of this question