Math, asked by Aish0001, 1 year ago

find the value of k for which the points (3 k - 1, k - 2) , (k, k - 7) and (K - 1, - K - 2) are collinier

plz provide each and every step

Attachments:

Answers

Answered by Anonymous

Answer:

k = 3

Step-by-step explanation:

A = ( 3k-1, k-2 )

B = ( k , k-7 )

C = ( k-1, -k-2 )

Slope of line AB:

[ (k-7) - (k-2) ] / [ k - (3k-1) ]

= -5 / ( -2k + 1 )

Slope of line AC:

[ (-k-2) - (k-2) ] / [ (k-1) - (3k-1) ]

= -2k / -2k

= 1

A, B, C collinear

<=> line AB and line AC are the same line

<=> slope of AB = slope of AC

<=> -5 / ( -2k + 1 ) = 1

<=> -5 = -2k + 1

<=> 2k = 6

<=> k = 3

Anonymous: Hello. Hope this helps you. Plz mark it brainliest. Have a good day!

Aish0001: soory

Aish0001: but i wanted the method in which area of triangle formed by 3 points is zero

Anonymous: Ouch! How to make a simple problem look difficult! Oh well, we gotta do what we gotta do. Good luck!

Aish0001: ya

Aish0001: ok bye

Previous Question

Next Question