find the value of k for which the points are A(2,-3) B(1,2)and C(k,0) are collinear
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Answered by
2
Answer:
7/5
Step-by-step explanation:
the determinant of (2,3,1)
(1,2,1)
(k,0,1)
should be 0 as the determinant determines the area of triangle with the vertex at the three coordinates and such for 3 points on a line is 0.
hope you like the answer bro.
Answered by
0
Answer .Value ok is 7 by 5
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