find the value of k for which the points are collinear.
(i) (7, -2), (5, 1), (3,-k)
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Step-by-step explanation: collinear points have the gradient
Using (3; -k) and (5; 1)
Gradient 1= 1- (-k)/5-3
= 1 + k/2
Using (5; 1) and (7; -2)
Gradient 2= 1- (-2)/5-7
= 1+2/-2
= -3/2
Gradient 1= Gradient 2
1+k/2= -3/2
-2- 2k = 6. Cross multiply
-2k = 6+2
-2k = 8
k= -4
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