Find the value of k for which the polynomial x^3-4x^2+2x+k has 3 as its zero
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Given, x^3-4x^2+2x+k
p(3) = 0
= 3^3 - 4(3)^2 + 2 * 3 + k
= 27 - 36 + 6 + k
= -9 + 6 + k
= -3 + k
k = 3.
p(3) = 0
= 3^3 - 4(3)^2 + 2 * 3 + k
= 27 - 36 + 6 + k
= -9 + 6 + k
= -3 + k
k = 3.
Answered by
3
hope it will help u....
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