Math, asked by rosy68, 1 year ago

find the value of k for which the polynomial y^4+25y^2+15y+10y^3+k is divisible by y+7​

Answers

Answered by lokeshdash
2

Y+7=0

Y=-7

ATQ:

P(-7)=(-7)^4+25(-7)^2+10(-7)^3+K

=-2401+25(49)+(-3430)+K

-K =1225-2401-3430

=-1176-3430

-K =-4606

K=4606

Hence ,the value of k is 4606

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