find the value of k for which the polynomial y^4+25y^2+15y+10y^3+k is divisible by y+7
Answers
Answered by
2
Y+7=0
Y=-7
ATQ:
P(-7)=(-7)^4+25(-7)^2+10(-7)^3+K
=-2401+25(49)+(-3430)+K
-K =1225-2401-3430
=-1176-3430
-K =-4606
K=4606
Hence ,the value of k is 4606
Similar questions
Hindi,
6 months ago
Computer Science,
6 months ago
Math,
6 months ago
Physics,
1 year ago
Math,
1 year ago