Question

find the value of k for which the q.e is real and equal. 2x^2+kx+3=0

Answer 1

Its quadratic equation. so

2x² + kx + 3 = 0 has equal roots

Hence b² – 4ac = 0

ie.  (k)² – 4(2)(3) = 0

k2 – 24 = 0

k2 = 24

∴ k = ± 2√6