Question

find the value of k for which the quadratic eqn. 9x-3kx+k=0 has equal roots

Answer 1

a=9,b=-3,c=know as the equation has equal roots put the formula D=b×b-4acwhere the value of D is zero as the equation has equal roots then the valye of k will come 1/ 4.

Answer 2

Answer:

4

Step-by-step explanation:

9x^2 -3kx + k = 0

b^2-4ac = 0 for equal roots

a = 9

b = -3k

c = k

(-3k)^2 -4*9*k= 0

9k^2 = 36k

k = 4

now given eq will become

9x^2 - 12x + 4= 0

(3x-2)^2 = 0

x = 2/3 equal roots of equation