Question

Find the value of k for which the quadratic equation
2x2 + kx + 3 = 0 has two real equal roots​

Answer 1

Answer:

K = 3 .................

Answer 2

Answer:

K = ±2√6

Step-by-step explanation:

Given that,

• Quadratic equation ; 2x² + kx + 3 = 0.

On comparing with ax² + bx + c = 0 , We get ;

$\implies$ a = 2 , b = k , c = 3

Given, Roots are real and equal,

$\implies$ ${\sf{\red{Δ = 0}}}$

$\implies$ b² - 4ac = 0

$\implies$ (k)² - 4 × 2 × 3 = 0

$\implies$ k² - 24 = 0

$\implies$ k² = 24

$\implies$ ${\sf{\green {k = ±2√6}}}$

Hence,

• The value of k is ±2√6.