Question

Find the value of k for which the quadratic equation 4x²- 3kx+1=0. has two real equal roots

Answer 1

Hey✨✨✨✨✨

Here is your answer,⬇⬇⬇⬇

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a = 4, b = -3k , c = 1

b^2 - 4ac = 0

(-3k)^2 - 4 (4)(1) = 0

9k^2 = 16

k^2 = 16/9

k = +/- 4/3

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Hope it helps you!✔✔✔✔

Answer 2

HEY HERE IS YOUR ANSWER...

                         for two equal roots b^2 -4ac = 0

                         (3k)^2 - 4 (4 * 1) = 0

                         9k^2 - 16 =0

                         9k^2 = 16

                         k^2 = 16/9

                         k = √16/9

                         k = + or - 4/3

                  HOPE THIS WOULD BE HELPFUL TO YOU