Find the value of k for which the quadratic equation 4x² + kx + 3 =0 has equal roots.
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Answered by
52
Solution :
Compare given Quadratic equation
4x² + kx + 3 = 0 with ax² + bx + c = 0,
we get
a = 4 , b = k , c = 3
Discriminant ( D ) = 0 [ equal roots ]
=> b² - 4ac = 0
=> k² - 4×4×3 = 0
=> k² = 4 × 4 × 3
=> k = ± √(4×4×3)
=> k = ± 4√3
•••••
Compare given Quadratic equation
4x² + kx + 3 = 0 with ax² + bx + c = 0,
we get
a = 4 , b = k , c = 3
Discriminant ( D ) = 0 [ equal roots ]
=> b² - 4ac = 0
=> k² - 4×4×3 = 0
=> k² = 4 × 4 × 3
=> k = ± √(4×4×3)
=> k = ± 4√3
•••••
Answered by
9
Step-by-step explanation:
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