Question

find the value of k for which the quadratic equation 9x2-3x-2=0​

Answer 1

Answer:where is K #no k #no vslue

Step-by-step explanation:

Answer 2

Correct Question:

Find the value of k for which the quadratic equation 9x² - 3x + k = 0 has equal roots.

Answer:

k = 1/4

Note:

• An equation of degree 2 is know as quadratic equation .

• Roots of an equation is defined as the possible values of the unknown (variable) for which the equation is satisfied.

• The maximum number of roots of an equation will be equal to its degree.

• A quadratic equation has atmost two roots.

• The general form of a quadratic equation is given as , ax² + bx + c = 0 .

• A quadratic equation has atmost two roots .

• The discriminant of the quadratic equation is given as , D = b² - 4ac .

• If D = 0 , then the quadratic equation would have real and equal roots .

• If D > 0 , then the quadratic equation would have real and distinct roots .

• If D < 0 , then the quadratic equation would have imaginary roots .

Solution:

The given quadratic equation is ;

9x² - 3x + k = 0

Clearly , we have ;

a = 9

b = -3

c = k

We know that ,

The quadratic equation will have equall roots if its discriminant is equal to zero .

=> D = 0

=> (-3)² - 4•9•k = 0

=> 9 - 9•4•k = 0

=> 9•(1 - 4k) = 0

=> 1 - 4k = 0

=> 4k = 1

=> k = 1/4

Hence,

The required values of k is 1/4 .