Question

find the value of k for which the quadratic equation for X square + 5 x + 25 is equal to zero has equal roots​

Answer 1

$\bold {Given:-} \begin{cases} \sf{ {x}^{2} + 5x + 25 = 0.} \\ \sf{a = 1} \\ \sf{b = 5} \\ \sf{c = 25}\end{cases}$

$\large \underline {Solution:-}$

$\: \: \: D= {b}^{2} - 4ac. \\ \\ \: \: \: \: 0= {5}^{2} - 4 \times 1 \times 25. \\ \\ \: \: \: \: 0 = 25 - 100. \\ \\ \: \: \: \: 0 = - 75.$

So,

we can Say that

${ \huge \underline {\boxed{D < 0.}}}$