Question

find the value of k for which the quadratic equation K + 4 x square + K + 1 X + 1 is equal to zero has real roots​

Answer 1

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Answer 2

(k+4)x²+(k+1)x+1 has equal roots.

So, by using quadratic formula,

0=b²-4ac. {here, a=k+4, b=k+1. and c=1}

0=(k+1)² -4×(k+4)×1

0=k²+1+2k-4k-16

0=k²-15- 2k

(factorising)

0=k²-2k-15

0=k²-5k+3k-15

0=k(k-5)+3(k-5)

so, k=-3 or k=5