Question

find the value of K for which the quadratic equation kx(x-2)+6=0 has 2 equal roots ​

Answer 1

Answer:

PLEASE MARK BRAINLIEST

k=6

Step-by-step explanation:

kx(x-2)+6 can be written as k {x}^{2}  - 2kx + 6 = 0

it has equal roots  

Kx^2-2kx +6=0

Equal roots implies that D=0

This implies that b^2-4ac=0

(-2k)^2 -24k=0

4k^2-24k=0

4k(k-6)=0

4k=0

This implies that k=0

And k-6=0

This implies that k=6

Answer 2

Answer:

kx ( x - 2 ) + 6 = 0

=》 $\tt {kx^{2} - 2kx + 6 = 0}$

=》 $\tt {b^{2} - 4ac = 0}$

=》 $\tt {(-2k)^{2} - (4)(6k) = 0}$

=》 $\tt {4k^{2} = 24k}$

=》 k = 6