Question

Find the value of ‘k’ for which the quadratic equation kx2 – 5x + k = 0 have real roots.

Answer 1

real roots means b^2-4ac=0
comparing given eqñ by ax^2+bx+c=0
Therefore,a=k,b=-5,c=k
∆=b^2-4ac
=(-5)^2-4*k*k
=25-4k^2
4k^2=25
k^2=25/4
k=5/2

Answer 2

Answer:

The value of k are

$k<\pm\frac{5}{2}$

Step-by-step explanation:

Given the quadratic equation

$kx^2-5x+k$

we have to find the value of k for which the given quadratic equation have real roots.

If the roots are real

Comparing given equation by $ax^2+bx+c=0$

Therefore, a=k,b=-5,c=k

$b^2-4ac>0$

$(-5)^2-4(k)k>0$

$25-4k^2>0$

$25>4k^2$

$k^2<\frac{25}{4}$

$k<\pm\frac{5}{2}$

The value of k are

$k<\pm\frac{5}{2}$