Question

Find the value of k for which the quadratic polynomial 9x2-3x+k has equal zeros​

Answer 1

Answer:

any value other thann 27

Answer 2

The value of k is "$\frac{1}{4}$". Further explanation is given below.

Step-by-step explanation:

Given equation is:

9x²-3x+k

Now,

a = 9

b = -3

c = k

If it has equal zeros then, As we know,

b²-4ac = 0

On putting the values in the above equation, we get

(-3)²-3×9×k = 0

(-3×-3)-4×9×k = 0

9-4×9×k =0

9-36k = 0

9 = 36k

k = $\frac{9}{36}$

k = $\frac{1}{4}$

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