Question

Find the value of k for which the quadratic polynomial 9x2-3kx+k hs equal zeroes

Answer 1

Answer:

Step-by-step explanation:

9x2–3kx+k=0

For equal roots Determinant should be zero i.e. D=0

B2-4AC=0

9k2–4*k*9=0

9k(k-4)=0

K=0 and k=4

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