Question

Find the value of k for which the root of quadratic equation 2x^2-6x+k=0 are real and equal.

Answer 1

Answer:

k = 9/2

Step-by-step explanation:

Given :

the root of quadratic equation 2x^2-6x+k=0 are real and equal.

To find : the value of k

Solution :

For real and equal root of   quadratic equation discriminant(D) is zero.

D = b^2-4ac

D = 36 - 8k

0 = 36 - 8 k

8k = 36

k = 36/8

k = 9/2

please mark my answer as brainliest.