find the value of K for which the roots of equation 8kx(x-1)+1=0 are real and equal
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question is improper.
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Answer:
The answer is 1-1x
Explanation:
8Kx(x-1)+1=0
=0×x²-1x+1=0
=0-1x+1=0
=1-1x=0
=1-1x
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