Three 3 Ω resistors P, Q and R are connected as shown in the figure. Each of them dissipates energy
and can withstand a maximum power of 27 W without melting. Find the maximum current that flows
through the resistor P.
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Answer:
If they are connected in series:
Explanation:
R=3 ohm
P=27 W
now we know that P=I²R
i.e 27=I²×3
I²=9
I=√9
I=3A
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