FIND THE VALUE OF K FOR WHICH THE ROOTS OF THE EQUATION (K+4) x 2 + (K+1) x + 1 = 0 are real and equal.
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D=0
(k+1)^2-4*(k+4)*1=0
now solve this quadratic
so, answer k=5,-3
(k+1)^2-4*(k+4)*1=0
now solve this quadratic
so, answer k=5,-3
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