Question

Find the value of k for which the roots of the quadratic equation

9x²+ 8 kx +16=0 are real and equal.​

Answer 1

Answer:

k= 3

Step-by-step explanation:

Quadratic equations have equal roots when D = b^{2}b

2

- 4*a*c = 0

here a= 9, b=8k and c = 16

0 = (8k)^{2}(8k)

2

- 4*9*16

⇒ 0 = 64k^{2}k

2

- 576

⇒ 0 = [tex]k^{2} = 9

⇒ k = 3

Therefore for k = 3 the quadratic equation has equal roots.

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