Math, asked by sayantanisingha, 1 year ago

Find the value of k for which the roots of the quadratic equation (k+1)^2*x^2-2(k-1)*x+1=0 are equal.

Answers

Answered by adit22
3
Roots r equal so the discriminant =0
D=b^2-4ac
0= (2 (k-1)^2 )-(4 (k-1)^2)
0= 16k
k=0

sayantanisingha: Thank you
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