find the value of k for which the system of equations x+2y-3=0 and 5x+my+7=0 has no solution .
Anonymous:
hiii
hii
there's no k in both the equations
pls check the question it must be m instead of k
Answers
Answered by
2
Answer:
value of m can be any whole no. except 10
Step-by-step explanation:
i need step by step
can't u give me in steps
ya sure
condition for no solution is a1/a2 is not equal to b1/b2
so a1=1 and a2 = 5 , b1 = 2 b2 = m
so if m is 10 b1 / b2 will become 1/5
so m should not be equal to 10
it can be any whole no. except 10
is ti better ?
Answered by
2
The given equation be as:
x + 2y -3 = 0....(1)
5x + ky + 7 = 0....(2)For no solutiona1/a2 = b1/b2 is not equal to c1/c21/5 = 2/k is not equal to -3/71/5 = 2/kso value of k = 10Hence for no solution the value of k = 10Hope this helps...
Similar questions