Question

Find the value of K for which the system of linear equation has no solution​

Answer 1

Answer:

Answer

We know that the system of equations

a

1

x+b

1

y=c

1

a

2

x+b

2

y=c

2

has no solution, if

a

2

a

1

=

b

2

b

1



=

c

2

c

1

Here, a

1

=3,b

1

=1,c

1

=1,a

2

=2k−1,b

2

=k−1,c

2

=2k+1

So, the given system of equations will have no solution, if

2k−1

3

=

k−1

1



=

2k+1

1

2k−1

3

=

k−1

1

and

k−1

1



=

2k+1

1

Now,

2k−1

3

=

k−1

1

⇒3k−3=2k−1⇒k=2

Clearly, for k=2 we have

k−1

1



=

2k+1

1

Hence, the given system of equations will have no solution, if k=2.

Step-by-step explanation:

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Answer 2

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