Question

find the value of k for which(x-1) is a factor of the polynomial x^3-kx^2+11x-6​

Answer 1

Answer:

6

Step-by-step explanation:

f(x) = x^3 - kx^2 + 11x - 6

f(1) = 1^3 - k(1)^2 + 11(1) -6

= 1 - k + 11 - 6

= 12 - 6 - k

= 6 - k

Since (x-1) is a factor of the equation ;

Equating above equation to 0.

: 6-k= 0

k=6.

Answer 2

Step-by-step explanation:

In this question

$x {3} - kx ^{2} + 11x - 6 \\ put \: the \: value \: x = 1 \\ we \: get \\ (1)^3 - k(1) ^{2} + 11(1) - 6 = 0 \\ 1 - k + 11 - 6 = 0 \\ 12 - 6 - k = 0 \\ 6 - k = 0 \\ k = 6$