Math, asked by Nilesh8580, 1 year ago

Find the value of k for which x=1 is a root of equation x2+kx+3=0

Answers

Answered by nikita3811
3

Answer:

-4

Step-by-step explanation:

x2 + kx + 3 = 0

Put x= 1,

1+ K + 3 = 0

K= -4

Answered by aagarg2001
1

Answer:

k = -4

Step-by-step explanation:

x² + kx +3 =O

We know that x=1 is the root of equation

so put x=1

1+K +3 =0

so k=(-4)

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