Question

Find the value of k for which x=1 is a root of the equation x2+kx+3=0. Also,find the other root.

Answer 1

$\huge\boxed{\fcolorbox{cyan}{grey}{Solution:-}}$

Then put the value of x

$\sf {(1)}^{2}+k×1+3=0 \\ \sf 1+k+3=0 \\ \sf 4+k=0 \\ \sf k=(-4)$

Answer 2

$\huge\boxed{\fcolorbox{cyan}{white}{Solution:-}}$

Then put the value of x

$\sf {(1)}^{2}+k×1+3=0 \\ \sf 1+k+3=0 \\ \sf 4+k=0\\ \sf k=(-4)$