find the value of k for which x=1 is root of equation x²+kx+3=0.Also , find the other root.
Attachments:
Answers
Answered by
4
Mark this answer as brainliest answer
Attachments:
Answered by
6
Answer
Value of k
f (x)=x2+kx+3 =0 => f (1) =1+k+3=0
=> f (1) = k+4=0=>f (1) = k= - 4 .
Therefore the required polynomial will be
x^2 - 4x+3=0 .
Find the other root
f (x) =x^2 - 4x+3=0
=> x^2- 3x-x +3=0
=> x (x-3) -( x-3)=0
=> (x-3)(x-1)=0
Therefore , the other roots are 3 and 1 .
Hope it will help you then please mark me brainliest and follow me.
Similar questions