Question

find the value of k for which x=1 is root of equation x²+kx+3=0.Also , find the other root.

Answer 1

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Answer 2

Answer

Value of k

f (x)=x2+kx+3 =0 => f (1) =1+k+3=0

=> f (1) = k+4=0=>f (1) = k= - 4 .

Therefore the required polynomial will be

x^2 - 4x+3=0 .

Find the other root

f (x) =x^2 - 4x+3=0

=> x^2- 3x-x +3=0

=> x (x-3) -( x-3)=0

=> (x-3)(x-1)=0

Therefore , the other roots are 3 and 1 .

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