find the value of k for which x=-2 is a root of equation x/2+x-2= kx-1
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Answer:
if x is the root of the eqn
then substituting x=2 in the eqn
2/2+2-2=2k-1
1+0=2k-1
1+1=2k {transposing}
2=2k
k=2/2
k=2
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Answered by
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Answer:
k=2
Step-by-step explanation:
The root of Given equation is X=-2
•°• X/2+X-2=Kx-1
•°• -2/2+(-2)-2=k(-2)-1
•°• -2/2-2-2=-2k-1
•°• -2/2-8=-2k
•°• -2-8/2=-2k-1
•°•-10/2=-2k-1
•°• -5 = -2k - 1
•°• -5+1 = -2k
•°• -4 = -2k
•°• -4/-2=k
•°• k = 2
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