Math, asked by pjotmangatmangat, 8 months ago

Find the value of k for which x = - 2 is a root of quadratic equation kx²+x-6=0

Answers

Answered by mamtakumari2611976
0

Step-by-step explanation:

As x=-2 is a root of quadratic equation --> kx^2+x-6

therefore, putting x=-2

k×(-2)^2+(-2)-6=0

k×4-8=0

4k=8

k=8/4

k=2 Answer

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