Find the value of k for which x = - 2 is a root of quadratic equation kx²+x-6=0
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Step-by-step explanation:
As x=-2 is a root of quadratic equation --> kx^2+x-6
therefore, putting x=-2
k×(-2)^2+(-2)-6=0
k×4-8=0
4k=8
k=8/4
k=2 Answer
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