Question

Find the value of k for which x=2 is a solution of kx2+2x-3=0

Answer 1

Hii dear here is your answer

putting x=2 in equation so,
◆k(2)^2+2(2)-3=0
◆4k+4-3=0
◆4k+1=0
◆4k=-1

k=-1/4


hope it helps you....,☺☺

Answer 2

Answer:

The value of k is $-\frac{1}{4}$.

Step-by-step explanation:

The given equation is

$kx^2+2x-3=0$

If x=2 is a solution of the equation, then the equation must satisfy x=2.

$k(2)^2+2(2)-3=0$

$k(4)+4-3=0$

$4k+1=0$

$4k=-1$

$k=-\frac{1}{4}$

Therefore the value of k is $-\frac{1}{4}$.