Question

Find the value of k for which x=-2is a root of the quadrayic eqtn kx square+x-6=0

Answer 1

The value of k for which x=(-2) is the root of the quadratic equation is 2.


SOLUTION :-


$the \: quadratic \: equation \: is \\ \\ k {x}^{2} + x - 6 = 0 \\ \\ x = ( - 2) \: is \: root \: for \: the \: equation\\ \\ so \\ \\ k {( - 2)}^{2} - 2 - 6 = 0 \\ \\ 4k - 8 = 0 \\ \\ 4k = 8 \\ \\ k = \frac{8}{4} = 2 \\ \\ k = 2$


After putting x = (-2)

And, k = 2

We get that :-

$2 \times {( - 2)}^{2} - 2 - 6 \\ \\ = 8 - 8 \\ \\ = 0$


Thus,
Value for k is correct as we got the answer as 0 after putting the values of k and x.


Hence,

$k = 2$


Thanks!

Answer 2

Answer:

hey mate your ans is

2

Step-by-step explanation:

plz mark as brainlaist