Question

Find the value of k for which (x-4) is a factor of (2x3-3x2-18x+k)​

Answer 1

Answer:

Here's your answer

By factor theorem

(x-4) =0

x=4

So

$p(4) = 2 ({4}^{3} ) - 3 ({4}^{2} ) - 18(4) + k \\ \\ = 2 \times 64 - 3 \times 16 - 72 + k = 0 \\ \\ 128 - 48 - 72 + k \\ \\ 128 - 120 + k = 0 \\ \\ 8 + k = 0 \\ \\ \\ k = - 8$

Hope it helps! ✌

Answer 2

Answer:

please refer to the attachment.

I hope it would help you

thank you.

^_^