find the value of k forvthe quadratic equation 2x^2+kx+3=0
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2x2 + kx + 3 = 0 has equal roots Hence b2 – 4ac = 0 That is (k)2 – 4(2)(3) = 0 k2 – 24 = 0 k2 = 24 ∴ k = ± 2√6
( it is the the question no. 2 from ex 4.2 and it is also given that the equation has two equal roots.)
( it is the the question no. 2 from ex 4.2 and it is also given that the equation has two equal roots.)
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