Question

find the value of k from the following pair of equations have no solution
kx-8y = k+2
6x-3ky = 9

plz ans it step by step​

Answer 1

Given :

• kx - 8y = k + 2
• 6x - 3ky = 9

To Find :

• Value of k

Solution :

Condition for no solution is :

$\large \tt \implies \dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} \: \cancel = \: \dfrac{c_1}{2_2}$

Here

$\tt a_1 = k \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: a_2 = 6 \\ \\ \tt b_1 = - 8 \: \: \: \: \: \: \: \: \: \: \: \:b_2 = - 3k$

Substitute value in formula

$\tt \implies\dfrac{k}{6} = \frac{ - 8}{ - 3k} \\ \\\tt \implies- 3 {k}^{2} = - 48 \\ \\\tt \implies {k}^{2} = \frac{ - 48}{ - 3} \\ \\\tt \implies {k}^{2} = 16 \\ \\\tt \implies k = \sqrt{16} \\ \\ \tt \implies k = 4$

Answer 2

Answer:

k = 4

Step-by-step explanation:

If there is no solution , then

a1/a2 = b1/b2 ≠ c1/c2

Here,

a1 = k & a2 = 6

b1 = -8. &. b2 = -3k

Substituting the value in formula

=> k/6 = (-8)/(-3k)

=> -3k^2 = -48

=> k^2 = -48/-3

=> k^2 = 16

=> k = √16

=> k = √4×4

=> k = 4 Ans...

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