find the value of k from which the equation x^2+k( 2 X + K - 1 )+ 20 has equal roots
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x^2+2kx+k(k-1)+2
so,a=1,b=2k,c=k(k-1)+2
D=b^2-4ac
=D=(2k^2) -4*(k(k-1)+2)=0
=4k^2-4(k^2-k+2)=0
=4k^2 - 4k^2 + 4k - 8=0
=4k - 8 = 0
=k=2
so,a=1,b=2k,c=k(k-1)+2
D=b^2-4ac
=D=(2k^2) -4*(k(k-1)+2)=0
=4k^2-4(k^2-k+2)=0
=4k^2 - 4k^2 + 4k - 8=0
=4k - 8 = 0
=k=2
i hope it will work
no it is 80 not 8
and answer is 20 not 2
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