Question

Find the value of k,if -1 is a factor of the polynomial P(x)=2x²+kx+√2​

Answer 1

According to question,

Putting value of x in p(x)

P(-1) = 2 × (-1)²+ k × (-1) +√2=0

p(-1) = 2×1-k+√2=0

p(-1) = 2-k+√2=0

p(-1) = -k = -√2-2

p(-1) = k = 2√2.

Answer 2

Answer:

★Given:-

• 2x² + kx + √2 is a quadratic polynomial

★To Find:-

• Find Value of k, if -1 is factor

★Solution:-

Here -1 is factor, so we can substitute 1 in x. thus we can get answer,

→ 2(-1)² + k(-1) + √2 = 0

→ 2(1) + (-k) + √2 = 0

→ 2 - k + √2 = 0

→ 2 - k = -√2

→ -k = -√2 - 2

→ -k = -(√2 + 2)

→ k = √2 + 2

∴ The Value of k is √2 + 2