Question

Find the value of k if 2 is the zero of 3x^2-17x +k

Answer 1

That means if 2 is substituted in the equation the value will be 0.

So,
3(2)²-17(2)+k = 0
12 - 34 + k = 0
k = 22

Answer 2

given zero of given polynomial

x= 2

p(x) = 3x^2 - 17x + k

p(2) = 3(2)^2 - 17 ( 2 ) + k

p(2) = 12 - 34 + k

p(2)= - 22 + k

since ,2 is the zero of p(x) then p(2)= 0

therefore, - 22 + k = 0

this implies that ,k = 22
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Your Answer : k = 22
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