Question

find the value of k , if 2x+1 is a factor of (3x+2)x³+(k-1)​

Answer 1

Answer:

17/16

Step-by-step explanation:

p(x) = (3x+2)x³+(k-1)​

q(x) = 2x+1

q(x) = 0

2x+1 = 0

2x = -1

x = -1/2

= (3x+2)x² + (k-1) =            ( Substitute x with -1/2 )

= [ 3(-1/2) + 2] (-1/2)³ + ( k-1) = 0

= (-3/2+2) (-1/8) + (k-1) = 0

= ( -3/2 + 4/2) (-1/8) + (k-1) = 0          

= ( 1/2) (-1/8) + ( k-1) = 0

= ( -1/16) + (k-1) = 0

=  ( k -1) = 1/16

= k = 1/16 + 1

= k = 1/16+ 16/16 = 17/16