find the value of k, if 2x-1 is a factor of the polynomial 6x²+Kx-2
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Answered by
2
Answer:
Let P(x)=6x
3
−x
2
−4x+k
2x−1 is a factor of P(x)
⇒P(1/2)=0
6(
2
1
)
3
−(
2
1
)
2
−4(
2
1
)+k=0
6/8−1/4−4/2+k=0
6−2−16+8k=0
8k=12
k=3/2
Answered by
2
Step-by-step explanation:
2x-1 must be equal to 0 because it is a factor
i hope it will help you
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