Math, asked by thanmayyadavmende, 7 months ago

find the value of k if 3x+ky_1=0 7x_3y+3 are perpendicular​

Answers

Answered by banuazeez97
0

Step-by-step explanation:

3x−4y+5=0

⟹4y=3x+5

⟹y=34x+53

m1=34

3x+ky+10=0

⟹ky=−3x−10  

⟹y=−3kx−10k

m2=−3k

Two lines are parallel, if they have the same slope.

Setting  m1=m2  yields

34=−3k  

⟹14=−1k  

⟹k=−4

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