Question

find the value of k if 4 x cube minus 2 X square + kx + 5 leaves remainder -10 when divided by 2 X + 1 ​

Answer 1

The value of k when the polynomial $4x^{3}-2x^{2}+kx+5$ is divided by 2x + 1 and leaves a remainder -10 is 28.

• Given polynomial is

                $4x^{3}-2x^{2}+kx+5$

• It leaves remainder -10 when divided by 2x + 1

                ⇒ f(-1/2) = -10

                ⇒ $4(\frac{-1}{2})^{3}-2(\frac{-1}{2})^{2}+k(\frac{-1}{2})+5=-10$

                ⇒ $-\frac{1}{2}-\frac{1}{2}-\frac{k}{2}=-15$

                ⇒ $-\frac{k}{2}=-15+1$

                ⇒  $-\frac{k}{2}=-14$

               ⇒ k = 28

            ∴ The value of k is 28.

Answer 2

Answer:

answer is attached above please tell your reviews